Question

prove that logm÷n=logm-logn​

Answer 1

Answer:

log(m+n)= logm+ logn

log(m+n) = log(mn). [ loga+logb =log ab]

log on both sides gets cancel

then,

m+n = mn

=> m= mn -n

=> m = n(m-1)

=> n = m/m-1 [proved]

Step-by-step explanation:

i hope it's helpful