Question

prove that (m+n)*-1 (m*-1+n*-1)=(mn)*-1

Answer 1

HELLO DEAR,

${(m + n)}^{ - 1} ( {m}^{ - 1} + {n}^{ - 1} ) \\ \\ => \frac{1}{ {(m + n)}^{1} } \times ( \frac{1}{m} + \frac{1}{n} ) \\ \\ = > \frac{1}{(m + n)} \times \frac{(m + n)}{mn} \\ \\ = > \frac{1}{mn} = {(mn)}^{ - 1}$

I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Heya 

LHS 

(m+n)⁻¹ (m⁻¹ + n⁻¹) 

1/( m + n) ( 1/m + 1/n ) 

1/(m+ n) ( m + n) /mn 

1/mn 

(mn) ⁻¹ = RHS :D