Question

prove that m1 +p <or =m2
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Answer 1

m + 1/m = p - 2

Now square on both sides

(m + 1/ m)^2 = (p - 2)^2

m^2 + 1/m^2 + 2(m)(1/m) = p^2 + 4 - 4p

m^2 +1/m^2 + 2 = p^2 + 4 - 4p

m^2 + 1/m^2 = p^2 - 4p - 2

Thanks