prove that median of a triangle divides it into two equal parts
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ANSWER :-
Let ABC be a triangle and Let AD be one of its medians.
In △ABD and △ADC the vertex is common and these bases BD and DC are equal.
Draw AE⊥BC.
Now area(△ABD)=21×base×altitude of△ADB
=21×BD×AE
=21×DC×AE(∵BD=DC)
but DC and AE is the base and altitude of △ACD
=21× base DC × altitude of △ACD
=area△ACD
⇒area(△ABD)=area(△ACD)
Hence the median of a triangle divides it into two triangles of equal areas.
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Explanation:
just make a line in the middle of the triangle and there you go I answered your question
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