prove that median of tiangle divides it into two equal triangle
Answers
Answered by
1
In ΔABC, AD is the median
Hence BD = DC
Draw AE ⊥ BC
Area of ΔABD
= Area of ΔADC
Thus median of a triangle divides it into two triangles of equal area
Hence BD = DC
Draw AE ⊥ BC
Area of ΔABD
= Area of ΔADC
Thus median of a triangle divides it into two triangles of equal area
Answered by
1
draw triangle ABC ,
AD is the median
BD = DC-------(1)
draw AM ⊥ BC
arΔABD/arΔACD = (1/2*BD*AM)/(1/2*DC*AM)
= (1/2*BD*AM)/(1/2*BD*AM) [ from (1)]
= 1
∴ arΔABD /arΔACD =1
arΔABD = arΔACD
AD is the median
BD = DC-------(1)
draw AM ⊥ BC
arΔABD/arΔACD = (1/2*BD*AM)/(1/2*DC*AM)
= (1/2*BD*AM)/(1/2*BD*AM) [ from (1)]
= 1
∴ arΔABD /arΔACD =1
arΔABD = arΔACD
Similar questions