prove that medians of triangle divide it two triangle of equal area
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In ΔABC, AD is the median
Hence BD = DC
Draw AE ⊥ BC
Area of ΔABD
= Area of ΔADC
Thus median of a triangle divides it into two triangles of equal area
Hence BD = DC
Draw AE ⊥ BC
Area of ΔABD
= Area of ΔADC
Thus median of a triangle divides it into two triangles of equal area
Answered by
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let ABC be a triangle and let AD be one of its medians
to prove --ar(ABD)=ar(ACD)
const-draw AN perpendicular to BC
proof-of-concept ar(ABD)=1/2*base *height
ar(ABD)=1/2*BD*AN
ar(ABD)=1/2*CD*AN. (as BD=CD)
ar(ABD)=1/2*base *height (of triangle ACD)
ar(ABD)=ar(ACD)
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to prove --ar(ABD)=ar(ACD)
const-draw AN perpendicular to BC
proof-of-concept ar(ABD)=1/2*base *height
ar(ABD)=1/2*BD*AN
ar(ABD)=1/2*CD*AN. (as BD=CD)
ar(ABD)=1/2*base *height (of triangle ACD)
ar(ABD)=ar(ACD)
hope this will help u plz follow me and Mark it as brainliest plz plz plz plz
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