Question

Prove that n^2-n is divisible by 2 for every positive integers?

please please please

Answer 1

Hi Noonu1,
I think it would be thus:
n^2-n=n (n-1)
Here, if n is even then it is divisible by 2.
If n is odd, then (n-1) will be even, hence it would still be divisible by 2. So for every positive integer also.
Hope I helped.
Thanks!