prove that n^2 - n is divisible by 2 for every positive integer n
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n^2 -n = n(n-1) now for this to be divisible by 2, either n or (n-1) should be an even number. taking n as an odd number, (n-1) becomes an even number this divisible by 2. if n is an even number, the number is anyway divisible by 2.
lorengray:
r u sure this is the solution?
yep
no but id think ??!!!
cause if n is even n-1 will be odf
and won't divisible by 2
well if n is even, any number multiplied by an even number is always an even number. thus divisible by 2
eg, take n = 4, n(n-1) = 4(3) = 12 which is divisible by 2
thankyou sm..!
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