Question

prove that n*3 -n is divided by 6​

Answer 1

Step-by-step explanation:

f(n) = n³-n

=> put n=1 => f(1) = 1-1 = 0/6 = 0

=> put n=2 => f(2) = 2³-2 = 8-2 = 6/6 =1

=> put n=3 => f(3) = 3³-3 = 24/6 = 6

=> put n=4 => f(4) = 4³-4 = 60/6 = 10

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=> put n=n => f(n) = n³-n also divisible by 6.