Question

Prove that n^3-n is divisible by 6 for any positive integer n

Answer 1

Answer:

hey mate!!

any number in the form of n

3

−n=n(n+1)(n−1) is divisible by 2.

Since, the given number n

3

−n=n(n+1)(n−1) is divisible by both 3 and 2. Therefore, according to the divisibility rule of 6, the given number is divisible by 6.

Hence, n

3

−n=n(n+1)(n−1) is divisible by 6.

hope it is helpful for u!!✌❤