Question

Prove that - n+5! upon n+3! = n square+9n+20

Answer 1

Step-by-step explanation:

= (n+5)!/(n+3)!

= (n+5)(n+4)(n+3)!/(n+3)!

= (n+5)(n+4)

= n^2 +4n + 5n + 20

= n^2 + 9n + 20