Prove that (n²+n) is divisible by 2 for any positive integer n
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Step-by-step explanation:
we know that the square of even numbers is even and the square of odd numbers is odd.
2*2= 4
3*3= 9
4*4= 16
5*5= 25
and so on...
so,
(i) when n is odd, n*n is odd,
and when you add (n*n)+n , addition of two odd numbers Is always even so it is always divisible by 2.
(ii) when n is even, n*n is even,
and addition of two even numbers i.e. (n*n +n) is also even, hence divisible by 2.
therefore, (n*n +n) is divisible by 2 for any positive integer n.
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