prove that n²-n is divisible by two for every positive integer n.
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n² - n
= n ( n - 1 )
= ( n - 1 ) n.
So , n²-n is the product of two consecutive numbers.
We know that, In two consecutive numbers, one of them would be divisible by 2 .
Hence, the product would be divisible by 2 .
So, n²-n is divisible by 2 for every positive integer " n "
= n ( n - 1 )
= ( n - 1 ) n.
So , n²-n is the product of two consecutive numbers.
We know that, In two consecutive numbers, one of them would be divisible by 2 .
Hence, the product would be divisible by 2 .
So, n²-n is divisible by 2 for every positive integer " n "
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