prove that necessary and sufficient condition for the vector A,B and C to be co-planer ,if that their scaler tripple vector product A.B×C=0.
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a · [b × с] = 1 1 1 =
1 3 1
2 2 2
= 1·2·3 + 1·1·2 + 1·1·2 - 1·2·3 - 1·1·2 - 1·1·2 = 6 + 2 + 2 - 6 - 2 - 2 = 0
Answer: vectors are coplanar as their scalar triple product is zero
abhishek1619:
this is not proper answer.
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