prove that of all parallelograms of given sides the ractangle has the maximum area.
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Answer:
Area of ||gm = base × height or b × h
Area of rectangle = length × breadth or a × b
If you concentrate on ||gm then h is perpendicular and we are getting a small triangle where "a" is hypotenuse.
Since hypotensue is longest side in triangle,
a > h
Multiplying b both sides
a × b > h × b
Or,
Area of rectangle > Area of ||gm
chinu499:
diagnol draw in parallelogram
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