Question

prove that on dividing the polynomia 4x3 +3x2 +2x-9 by x-1 the remainder is zero
​

Answer 1

If the remainder is zero, it is divisible by x-1.

→ 4x³+3x²+2x-9 = (x-1)Qₓ+R

To remove Qₓ, let's multiply zero in front of it. It is required that x-1=0 now. (x=1)

→ 4+3+2-9 = 0Qₓ+R

→ 0 = R

It is divisible by x-1.