Question

Prove that one and only one out of n, (n + 2) and (n + 4) is divisible by 3. Where 'n' is any positive integer.

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Answer 1

Answer:

refer to the attachment

Answer 2

We know that any positive integer of the form 3q or, 3q+1 or 3q+2 for some integer q and one and only one of these possibilities can occur.

So, we have following cases:

Case-I: When $\orange{n=3q}$

In this case, we have

$\red{n=3q}$, which is divisible by 3

Now,$\blue{n=3q}.$

$\red{n+2=3q+2}$

n+2 leaves remainder 2 when divided by 3

Again,$\red{n=3q}$

$\red{n+4=3q+4=3(q+1)+1}$

n+4 leaves remainder 1 when divided by 3

n+4 is not divisible by 3.

Thus, n is divisible by 3 but n+2 and n+4 are not divisible by 3.

Case-II: when n=3q+1

In this case, we have

$\green{n=3q+1,}$

$\red{n}$ leaves remainder 1 when divided by 3.

$\red{n}$ is divisible by 3

Now, $\orange{n=3q+1}$

$\orange{n+2=(3q+1)+2=3(q+1)}$

n+2 is divisible by 3.

Again, $\red{n=3q+1}$

$\orange{n+4=3q+1+4=3q+5=3(q+1)+2}$

n+4 leaves remainder 2 when divided by 3

n+4 is not divisible by 3.

Thus, n+2 is divisible by 3 but n and n+4 are not divisible by 3.

Case-III: When n=3q+2

In this case, we have

n=3q+2

n leaves remainder 2 when divided by 3.

n is not divisible by 3.

Now, n=3q+2

n+2=3q+2+2=3(q+1)+1

n+2 leaves remainder 1 when divided by 3

n+2 is not divisible by 3.

Again, n=3q+2

n+4=3q+2+4=3(q+2)

n+4 is divisible by 3.

Hence, n+4 is divisible by 3 but n and n+2 are not divisible by 3.