Question

prove that one by 1 + cos theta + 1 by 1 minus cos theta is equal to 2 cos square theta​

Answer 1

Answer:

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$lhs = \frac{1}{1 + \cos( \alpha ) } + \frac{1}{1 - \cos( \alpha ) } \\ = \frac{1 - \cos( \alpha ) + 1 + \cos( \alpha ) }{1 - { \cos( \alpha ) }^{2} } \\ = \frac{2}{ { \sin( \alpha ) }^{2} } \\ = 2 { \csc( \alpha ) }^{2}$

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Answer 2

Answer:

the answer is in the photo

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