Question

) Prove that one of any three consecutive positive integers
must be divisible by 3​

Answer 1

If n = 3p + 1, then n + 2 = 3p + 1 + 2 = 3p + 3 = 3(p + 1) is divisible by 3. So, we can say that one of the numbers among n, n + 1 and n + 2 is always divisible by 3.

Answer 2

Answer:

you use calculater OK!!!!!!!

Step-by-step explanation:

BYB BYB