Question

Prove that one of any three consecutive positive integers must be divisible by 3.

Answer 1

hii mate here is the answer to your question
let, the three consecutive positive integers be x, (x+1), and (x+2)
now, you can have a check on it
umm let's check it
x+x+1+x+2/3=3x+3/3=x+1.(proved)
hope this helps
keep smiling

Answer 2

let 3 consecutive positive integers be P,p+ 1 and P+2
whenever a number is divided by 3,the remainder we gets it either 0,or 1, 2 .
:
therefore:
P=3q 3q+1 or 3q+2 , where q is some integer
if P =3qthen n is divisible by 3
if P = 3q +1,then n+2 =3q +1+2=3q +3= 3(q+1) is divisible by 3
if P = 3q+2 ,then n +1 =3q +2+1 =3q + 3=3(q+1) is divisible by 3
thus, we can state that one of the number among P,p+ 1 and P+2 is always divisible by 3
I hope it helps
thank
mark plz brainiest