Question

prove that one of every consecutive positive integer is divisible by 7

Answer 1

Answer:

Step-by-step explanation:

let n, n+1, n+2 be the three consecutive positive integers. we know that n is in the form of 3q, 3q+1, 3q+2.

Case -1, when n=3q n is divisibe nut n+1 & n+2 are not divisible.

Case-2, when n=3q+1 , n+2= 3q+3= 3(q+1) it is divisible by 3 but n+1 & n are not divisible by 3

Case-3, when 3q+2 , n+1= 3q+3 = 3(q+1) it is divisible by 3 but n+2 & n are not divisible. hence none of the situation is possible for 3 consecutive no divisible by 3