Question

prove that one of every three consecutive posetive integer is divisible by 3​

Answer 1

Answer. Let three consecutive positive integers be n, n + 1 and n + 2. If n = 3p + 2, then n + 1 = 3p + 2 + 1 = 3p + 3 = 3(p + 1) is divisible by 3. So, we can say that one of the numbers among n, n + 1 and n + 2 is always divisible by 3.