Question

prove that one of every three consecutive positive integers is divisible by 2​

Answer 1

Answer:

let the integer be be x

Step-by-step explanation:

so three consecutive integers are x-1,x,x+1

and we know every integer is in the form of 2n+1

so

2n+1-(1),2n+1,2n+1+(1)

2n,2n+1,2n+2

it is clearly visible that 2n is divisible by 2

so hence proved.

fact: two in three numbers are divisible by 2