prove that one of every three consecutive positive integers is divisible by 2
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Answer:
let the integer be be x
Step-by-step explanation:
so three consecutive integers are x-1,x,x+1
and we know every integer is in the form of 2n+1
so
2n+1-(1),2n+1,2n+1+(1)
2n,2n+1,2n+2
it is clearly visible that 2n is divisible by 2
so hence proved.
fact: two in three numbers are divisible by 2
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