Question

Prove that one of every three consecutive positive integers is divisible by 3..

Answer 1

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Let three consecutive positive integers be n, n + 1 and n + 2.

Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2.

∴ n = 3p or 3p + 1 or 3p + 2, where p is some integer.

If n = 3p, then n is divisible by 3.

If n = 3p + 1, then n + 2 = 3p + 1 + 2 = 3p + 3 = 3(p + 1) is divisible by 3.

If n = 3p + 2, then n + 1 = 3p + 2 + 1 = 3p + 3 = 3(p + 1) is divisible by 3.

So, we can say that one of the numbers among n, n + 1 and n + 2 is always divisible by 3.


HOPE IT HELPS U !!!

Answer 2

Given; that the Divisor is 3

To Find; that one of every three consecutive positive integers is divisible by 3

Solution; This question can be easily solved by letting three consecutive positive integers like 5,6 and 7

Here we notice that six is divisible by two

Hence proved