Math, asked by broke, 1 year ago

Prove that one question

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uniquegirl288: hlo broke

uniquegirl288: Mai shina

Answers

Answered by NamanSinghal1

$8 - 5 + 2 \times 2 \div (7 - 2) \times 7 \div 3 \times 0$
This is a common rule

If there are multiple terms in divide downwards then there's a reciprocal of the two terms and they are multiplied.

Hence it is multiplied by 0 at the last and the answer obyesly comes 0

Answered by manshi999

8 - 5 + 2 \times 2 \div (7 - 2) \times 7 \div 3 \times 08−5+2×2÷(7−2)×7÷3×0

This is a common rule

If there are multiple terms in divide downwards then there's a reciprocal of the two terms and they are multiplied.

Hence it is multiplied by 0 at the last and the answer obyesly comes 0

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