Math, asked by sania5804, 11 months ago

prove that one upon 3 + root 7 + 1 upon root 2 + root 7 + 5 + 1 upon root 2 + root 5 + root 3 + 1 upon root 3 + 1 is equals to 1​

Answers

Answered by adityachopade5
0

if u get sum of all this then this sum means that equation get cancel u may able to get a correct answer....that is 1

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