Prove that OP=2AP If AP and BP are two tangents and angle APB=120 degree.
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Step-by-step explanation:
Given: O is the centre of the circle. PA and PB are tangents drawn to a circle and ∠APB = 120°.
To prove: OP = 2AP
Proof:
In ΔOAP and ΔOBP,
OP = OP (Common)
∠OAP = ∠OBP (90°) (Radius is perpendicular to the tangent at the point of contact)
OA = OB (Radius of the circle)
∴ ΔOAP ≅ ΔOBP (RHS congruence criterion)
⇒ ∠OAP = ∠OBP = 120°/2 = 60°
In ΔOAP,
cos ∠OPA = 60° = AP/OP
∴ 1/2 = AP/OP
⇒ OP = 2 AP
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