Question

prove that op bisects AOB​

Answer 1

Answer:

In right ΔOLP & ΔOMP

PL = PM (given in the question)

OP = OP (common for both the triangles)

angle OLP = angle OMP (since PL perpendicular OA & PM perpendicular to OB)

Therefore, ΔOLP congruent to ΔOMP (SAS congruence condition)

So,

angle LOP = angle POM (CPCT)

i.e. OP bisects angle AOB

(Hence Proved)

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