prove that opp angles of parallelogram are equal
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Construction: Draw a parallelogram ABCD with AC as diagonal
Prove = angle A = angle C
& angle B = angle D
Proof = Opposite side of parallelogram is parallel then AB||DC & AD||BC
since , AB||DC & AC is transversal
then , angle BAC = angle DCA. ------ (1) ( by alternate interior angles )
similarly ,
AD||BC & AC is transversal
angle DAC = angle BCA -----(2)
Adding eqn 1 & 2 we get ,
angle BAD = angle DCB ( Hence Proved )
captainkhan85:
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To prove that the opposite angles of a parallelogram are equal.
Construction: Draw a parallelogram ABCD. Join BD.
Proof: In triangle ABD and BCD
AB = CD [opposite sides of the parallelogram]
BC = DA [opposite sides of the parallelogram]
BD is common
So triangles ABD and BCD are congruent.
Hence <A = <C , sides opposite BD.
Similarly <B = <D.
Therefore, the opposite angles of a parallelogram are equal.
Proved.
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