prove that: opposite angle of two equal side of an isosceles triangle same
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Given : An isosceles triangle
To Find : prove that: opposite angle of two equal side of an isosceles triangle same
Solution:
Let say Triangle ABC
AC = BC
Take Mid point of AB as D , Join AD
Now in Δ ADC and Δ BDC
AD = BD as D is mid point
DC = DC Common
AC = BC given
=> Δ ADC ≅ Δ BDC
=> ∠A = ∠B
QED
Hence Proved
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