Prove that opposite angles of a cyclic quadrilateral are supplementary
Answers
Hence, it is proved that the opposite angles of a cyclic quadrilateral are supplementary(sum of 180°).
Step-by-step explanation:
Let PQRS be the cyclic quadrilateral
To prove:
∠P + ∠R = 180°
∠Q + ∠S = 180°
Construction: Assume O as the centre of the circle. Now, Join O to Q and S. Then allow the angle subtended by the major and minor arc be a° and b°
Proof:
a° = 2∠R ...(1)
b° = 2∠P ...(2) (∵ Angle at center theorem)
By adding the equations (1) & (2),
a° and b° = 2∠R + 2∠P ...(3)
yet a° + b° = 360° ...(4)
From equations (3) & (4), we get
2∠R + 2∠P = 360°
∠R + ∠P = 360°/2
∵ ∠R + ∠P = 180°
Now,
∠P + ∠Q + ∠R + ∠S = 360° (∵ angle sum property of a quadrilateral)
∠Q + ∠S + 180° = 360° (∵ ∠R + ∠P = 180°)
∠Q + ∠S = 360° - 180°
∵ ∠Q + ∠S = 180°
Hence proved that opposite angles of a cyclic quadrilateral are supplementary.
Learn more: Supplementary angles
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