Prove that:
Opposite angles of a cyclic quadrilateral
are supplementary.why
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Given :- O is the centre of circle. ABCD is the cyclic quadrilateral.
To prove :- ∠BAD + ∠BCD = 180°, ∠ABC + ∠ADC = 180°
Construction : Join OB and OD
Proof :-
=> (i) ∠BAD = (1/2)∠BOD.
(The angle substended by an arc at the centre is double the angle on the circle.)
=> (ii) ∠BCD = (1/2) reflex ∠BOD.
=> (iii) ∠BAD + ∠BCD = (1/2)∠BOD + (1/2) reflex ∠BOD.
=> Add (i) and (ii).
∠BAD + ∠BCD = (1/2)(∠BOD + reflex ∠BOD)
∠BAD + ∠BCD = (1/2) ⋅ (360°)
(Complete angle at the centre is 360°)
∠BAD + ∠BCD = 180°
=> (iv) Similarly ∠ABC + ∠ADC = 180°.
I hope this will help you dear..
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