Prove that Opposite side of Parallelogram are Parallel .
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R.E.F image
In triangle ADC and ABC,
∠DAC=∠ACB(AB∥CD and taking AC as transversal)
AC=AC (common)
∠DCA=∠BAC(AB∥CD taking AC as transversal)
By ASA criterion of concurrency triangle ADC is congruent to triangle ABC.
AD=BC (By CPCT)
AB=CD (By CPCT)
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