Question

prove that opposite sides of parallelogram are congruent​

Answer 1

Step-by-step explanation:

let's draw two triangles named adc and abc

In triangle ADC and ABC,

∠DAC=∠ACB(AB∥CD and taking AC as transversal)

AC=AC (common)

∠DCA=∠BAC(AB∥CD taking AC as transversal)

By ASA criterion of concurrency triangle ADC is congruent to triangle ABC.

AD=BC (By CPCT)

AB=CD (By CPCT)