prove that out of any two consecutive positive integers one and only one in even is even
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Answered by
24
Let two consecutive positive integers are n and n + 1.
on dividing n by 2, let q be the quotient and r be the remainder .
using Euclid division Lemma :
n = 2q + r where 0< or =r <2.
therefore r=1,2
CASE 1. when r=0
n = 2q (even)
n+1 =2q +1 (odd)
CASE 2. when r =1
n =2q +1 (odd)
n+1 =2q+1+1
=2q+2
=2(q+1) ( even)
Hence out of any two consecutive positive integers one and only one is even.
Hope the answer helps you.
sanyukta60:
thanks a lot❤
Answered by
4
Refer to the attachment for the solution :)
Thnx✌️♥️~
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