Question

prove that OX bisects angle POQ.​

Answer 1

In ∆s BOX & AOX,

OX=OX(COMMON)

ang. OBX=ang. OAX(90°)

BX=AX(GIVEN)

SO, ∆BOX≅∆AOX (BY SAS)

So, ang. BOX=ang.AOX ( BY CPCT) ..... (1)

and, ang. POQ=ang.BOX+ang.AOX

=>ang.POQ=1/2 ang. BOX and ½ang.AOX (from 1)

Therefore, OX bisects angle POQ

Answer 2

please mark my answer as a brain list