Prove that P(A) U P(B) = P(A U B)
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For any set A , we let P(A) denotes the power set of A i.e. the set of all subsets of A . We will show that:
P(A)∪P(B)⊆P(A∪B)
Since A⊂A∪B , so every subset of A is also a subset of A∪B , therefore P(A)⊆P(A∪B) . Likewise, P(B)⊆P(A∪B) . Therefore, P(A)∪P(B)⊆P(A∪B) .
P(A∪B)⊈P(A)∪P(B)
Suppose A={1} , B={2} . So, A∪B={1,2} .
P(A)={∅,{1}}, P(B)={∅,{2}}
P(A∪B)={∅,{1},{2},{1,2}}⊈{∅,{1},{2}}=P(A)∪P(B)
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Agar aapko maths aata hai to please solve kardo it's my request
Brothers sorry but aaap ne Jo abhi apni mehnat se solve kiya uska answer =28.28 aa rha Hai
22 nhi
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