Question

prove that parallelogram on the same base and between the same parallels are equal in area ​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

In triangle AED and triangle BCF,

angle DAE=angle CBF(Corresponding angles)

angle AED=angle BFC(Corresponding angles)

so angle ADE=angle CBF(Angle sum property of triangle)

so triangle AED is congruent to triangle BCF(ASA congruence)

So area of both these triangles are equal.

Now we add common area EDCB to both areas

so

area AED + area EDCB = area BCF + area EDCB

= area ADCB = area FCDE

Hence proved.