Math, asked by Naveensankar007, 11 months ago


prove that parallelograms on the same base and between the same parallels are equal in
area.

Answers

Answered by Cosmique
1

Answer:

Step-by-step explanation:

Attachments:
Answered by harshkum2004
0

Answer:

Hence Proved

Step-by-step explanation:

As we know the area of parallelogram is

Base *Height

As the bases are same so the length of base of 1st and second are equal and

As the parallelogram are between same parallels so the height is also same as the height between parallels remain constant.

Therefor area =b*h

That is same

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