prove that parallelograms on the same base and between the same parallels are equal in
area.
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Step-by-step explanation:
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Hence Proved
Step-by-step explanation:
As we know the area of parallelogram is
Base *Height
As the bases are same so the length of base of 1st and second are equal and
As the parallelogram are between same parallels so the height is also same as the height between parallels remain constant.
Therefor area =b*h
That is same
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