prove that please...
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Answer: As 1+tan²Ф=sec²Ф
LHS ; sec²Ф+sec²Ф/tan²Ф
=sec²Ф(sec²Ф/tan²Ф)
=(1/cos²Ф)(1/cos²Ф)(cos²Ф/sin²Ф)
=1/sin²Фcos²Ф=1/(1-sin²Ф)(sin²Ф)
=1/[sin²Ф-sin²Фsin²Ф]
=RHS
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