Question

prove that



please fast. ​

Answer 1

Answer:

hope this will help you

Step-by-step explanation:

=tan(2×2θ)

= 2tan(2θ)/1−tan²(2θ)

= 2[ 2tanθ/1−tan ²θ]/1-[2tanθ/1−tan ²θ]]

= (4tanθ/1−tan ²θ)/((1−tan ²θ)²-4tan²θ/(1-tan²θ))

=(4tanθ(1−tan² θ)/((1−tan²θ) 2 −4tan² θ)

= 4tanθ(1−tan²θ)/1-6tan²θtan⁴θ