Question

prove that please help me​

Answer 1

Answer:

above is the pic

Step-by-step explanation:

I hop it's help

Answer 2

$\huge\mathcal\colorbox{navy}{{\color{cyan}{(☞∀ŋʂᏯɛཞ࿐)}}}$

Step-by-step explanation:

The following proof is a proof by contradiction.

Let us assume that √6 is rational number.

Then it can be represented as fraction of two integers.

Let the lowest terms representation be:

√6 = a/b

Note that this representation is in lowest terms and hence, a and b have no common factors

a ² =6b²

From above a ² is even. If a² is even, then a should also be even.

⟹a=2c

4c² = 6b²

2c²=3b²

From above 3b² is even. If 3b² is even, then b² should also be even and again b is even.

But a and b were in lowest form and both cannot be even. Hence, assumption was wrong and hence,

6

is an irrational number.

HØPÊ ÎT HÈLPẞ YØÜ ☃️☄️...