Prove that please please please please????
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ritvikjain2090ow0ydl:
root3=sin theta?
What
after if
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hello,
we know that
√3=P/H
P=√3k,H=k where k is a constant
we know that H²=P²+B²
k²=(√3k)²+B²
B²=3k²+B²
B²=-2k²
B=√-2k²
B=k√-2
which is not a real no.
hence,it will not be a real no.
we know that
√3=P/H
P=√3k,H=k where k is a constant
we know that H²=P²+B²
k²=(√3k)²+B²
B²=3k²+B²
B²=-2k²
B=√-2k²
B=k√-2
which is not a real no.
hence,it will not be a real no.
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