Question

prove that-

please solve it​

Answer 1

Answer:

Step-by-step explanation:

Given :

To prove the value :

$\frac{2^{30} + 2^{29} + 2^{28}}{2^{31} + 2^{30} - 2^{29}} =\frac{7}{10}$

Proof :

$LHS = \frac{2^{30} + 2^{29} + 2^{28}}{2^{31} + 2^{30} - 2^{29}}$

⇒ $\frac{2^{28 + 2} + 2^{28 + 1} + 2^{28 + 0}}{2^{28 + 3} + 2^{28 + 2} - 2^{28 + 1}}$

⇒ $\frac{2^{28}(2^2 + 2^{1} + 2^{0})}{2^{28}(2^3 + 2^{2} - 2^{1})}$

⇒ $\frac{2^2 + 2^1 + 2^0}{2^3 + 2^2 - 2^1}$

⇒ $\frac{4 + 2 + 1}{8 + 4 - 2}$

⇒ $\frac{7}{10} = RHS$

Hence proved,.