Question

PROVE THAT

pls answer ​

Answer 1

Step-by-step explanation:

CosA=2√m/(m+1)

or,Cos^2A=4m/(m+1)^2=4m/(m^2+2m+1)

we know, Sin^2A + Cos^2A=1

or, 1-Cos^2A= Sin^2A

or,1-{4m/(m^2+2m+1)}=Sin^2A

or,(m^2+2m+1-4m)/(m^2+2m+1)=Sin^2A

or,(m^2-2m+1)/(m^2+2m+1)=Sin^2A

or,(m-1)^2/(m+1)^2=Sin^2A

or,(m-1)/(m+1)=SinA

or,1/SinA=(m+1)/(m-1)

or,CosecA=(m+1)/(m-1)