prove that points ( 4,3) (7,-1) and (9,3) are the vertices of an isosceles triangles
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An isosceles triangle is a triangle with (at least) two equal sides.
Formula: Distance between two points= (x2–x1)2+(y2–y1)2−−−−−−−−−−−−−−−−−√(x2–x1)2+(y2–y1)2
A=(4,3)A=(4,3) B=(7,−1)B=(7,−1) C=(9,3)C=(9,3)
|AB|=(7–4)2+(−1–3)2−−−−−−−−−−−−−−√|AB|=(7–4)2+(−1–3)2
|AB|=(3)2+(−4)2−−−−−−−−−−√|AB|=(3)2+(−4)2
|AB|=9+16−−−−−√|AB|=9+16
|AB|=2–√5|AB|=25
|AB|=5|AB|=5
Similarly,
|AC|=(9–4)2+(3–3
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