Math, asked by pinkvforever, 17 days ago

Prove That Δ PQS ≅ Δ PRS given that QS = RS = 5cm, and ∠PSQ = ∠PSR .


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Answered by brainlyanswerer83
20

Hey Mate,

Given Question:-

→ Prove That Δ PQS ≅ Δ PRS given that QS = RS = 5cm, and ∠PSQ = ∠PSR .

To Prove :-

→ Δ PQS ≅ Δ PRS

Solution:-

Proof :-

→ In Δ PQS and Δ PRS,

→ We have,

→ QS = RS = 5cm   [ ∵ Given ]

→ ∠PSQ = ∠PSR     [ ∵ Given ]

→ PS = PS               [ ∵ Common side ]

→ ∴ Δ PQS ≅ Δ PRS  [ ∵ By SAS Congruency]

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Similar Question:-

→ Prove that Δ QSO ≅ Δ QMO, given that SO = MO = 5cm, ∠QOS = ∠QOM.

→ ( Hint : Refer the attachment )

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