Prove That Δ PQS ≅ Δ PRS given that QS = RS = 5cm, and ∠PSQ = ∠PSR .
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→ Hey Mate,
→ Given Question:-
→ Prove That Δ PQS ≅ Δ PRS given that QS = RS = 5cm, and ∠PSQ = ∠PSR .
→ To Prove :-
→ Δ PQS ≅ Δ PRS
→ Solution:-
→ Proof :-
→ In Δ PQS and Δ PRS,
→ We have,
→ QS = RS = 5cm [ ∵ Given ]
→ ∠PSQ = ∠PSR [ ∵ Given ]
→ PS = PS [ ∵ Common side ]
→ ∴ Δ PQS ≅ Δ PRS [ ∵ By SAS Congruency]
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→ Similar Question:-
→ Prove that Δ QSO ≅ Δ QMO, given that SO = MO = 5cm, ∠QOS = ∠QOM.
→ ( Hint : Refer the attachment )
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