Prove that product of any 2 consecutive number is divisible by 2
Answers
Answered by
0
Step-by-step explanation:
n(n+1)=n²+1
=((n+1)−1)(n+1)
=(n+1)² −(n+1)
So if (n+1) is an even no (n+1)² is even and diff of even is always even is (n+1).
If odd then (n+1)² is odd and diff of odd is always even
So n(n+1) is always even and divisible by 2
plz mark as brainliest answer .
Similar questions
Math,
4 months ago
Math,
4 months ago
Social Sciences,
8 months ago
Social Sciences,
11 months ago
Social Sciences,
11 months ago