Math, asked by soumyadeepmah8453, 8 months ago

Prove that product of any 2 consecutive number is divisible by 2

Answers

Answered by snigdhanayak774
0

Step-by-step explanation:

n(n+1)=n²+1

=((n+1)−1)(n+1)

=(n+1)² −(n+1)

So if (n+1) is an even no (n+1)² is even and diff of even is always even is (n+1).

If odd then (n+1)² is odd and diff of odd is always even

So n(n+1) is always even and divisible by 2

plz mark as brainliest answer .

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