Question

prove that product of every three consecutive positive integer is divisible by 6​

Answer 1

Answer:

Since any positive integer is of the form 6q or 6q + 1 or 6q + 2 or 6q + 3 or 6q + 4, 6q + 5. n (n + 1) (n + 2) = 12 (3q + 1) (2q + 1) (3q + 2), Which is divisible by 6.

Answer 2

Answer:

Since any positive integer is of the form 6q or 6q + 1 or 6q + 2 or 6q + 3 or 6q + 4, 6q + 5. n (n + 1) (n + 2) = 12 (3q + 1) (2q + 1) (3q + 2), Which is divisible by 6.

Step-by-step explanation:

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