prove that product of three consecutive positive integer is divisible by 6
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Let three consecutive positive integers be, n, n + 1 and n + 2. When a number is divided by 3, the remainder obtained is either 0 or 1 or 2.
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1×2×3=6
4×5×6=120
7×8×9=504
these all numbers are divided by 6
4×5×6=120
7×8×9=504
these all numbers are divided by 6
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